Comments on: How to find IP addresses and subnet number in a few seconds http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/ Source of IT knowledge Thu, 09 Feb 2012 17:22:01 +0000 hourly 1 http://wordpress.org/?v=3.3.1 By: chetshttp://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/comment-page-3/#comment-10172 chets Mon, 30 Jan 2012 09:57:49 +0000 http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/#comment-10172 so interesting method so interesting method

]]> By: desarhttp://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/comment-page-3/#comment-10121 desar Mon, 09 Jan 2012 21:21:40 +0000 http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/#comment-10121 Great work! Thank you very much indeed. The best article about sub netting calculations. Great work! Thank you very much indeed. The best article about sub netting calculations.

]]> By: giobithttp://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/comment-page-3/#comment-10112 giobit Sat, 07 Jan 2012 11:42:51 +0000 http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/#comment-10112 The interesting octet is the 4th at 192. Figure 256-192=64, the magic number. 64 is greater than 11. What then? if greater write 0 subnet 192.168.10.0 magic 64-1=63 this is bcast bcast (63-1)= last ip address 192.168.10.62 first ip 192.168.10.1 remember the subnet mask controls only network portion and host portions. when mask increasing the host was reduction. The interesting octet is the 4th at 192. Figure 256-192=64, the magic number. 64 is greater than 11. What then?

if greater write 0
subnet 192.168.10.0 magic 64-1=63 this is bcast
bcast (63-1)= last ip address 192.168.10.62
first ip 192.168.10.1

remember the subnet mask controls only network portion and host portions. when mask increasing the host was reduction.

]]> By: giobithttp://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/comment-page-3/#comment-10111 giobit Sat, 07 Jan 2012 11:16:05 +0000 http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/#comment-10111 Meraj Says: June 5th, 2009 at 4:11 am :DDD So the subnet number = 172.16.2.128 172.16.2.0 /25 masc bit never change the subnet when last is .0 Meraj Says:
June 5th, 2009 at 4:11 am

:D DD So the subnet number = 172.16.2.128

172.16.2.0 /25 masc bit never change the subnet when last is .0

]]> By: Jeaninehttp://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/comment-page-3/#comment-10061 Jeanine Wed, 14 Dec 2011 20:12:37 +0000 http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/#comment-10061 What is the magic number is greater than the number in the 4th octet? Example: IP address 192.168.10.11 Mask 255.255.255.192 The interesting octet is the 4th at 192. Figure 256-192=64, the magic number. 64 is greater than 11. What then? Thank you, Jeanine What is the magic number is greater than the number in the 4th octet? Example:

IP address 192.168.10.11
Mask 255.255.255.192

The interesting octet is the 4th at 192. Figure 256-192=64, the magic number. 64 is greater than 11. What then?

Thank you, Jeanine

]]> By: Johnhttp://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/comment-page-3/#comment-10026 John Tue, 06 Dec 2011 23:18:09 +0000 http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/#comment-10026 If I borrow 4 bits from a default mask. What is the subnet incrementation value, or delta? If I borrow 4 bits from a default mask. What is the subnet incrementation value, or delta?

]]> By: kamalhttp://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/comment-page-3/#comment-10014 kamal Sun, 04 Dec 2011 09:07:29 +0000 http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/#comment-10014 an organization is granted the block 21.34.24.0/14...find the first and last adress of block????i tried bt still confused:( an organization is granted the block 21.34.24.0/14…find the first and last adress of block????i tried bt still confused:(

]]> By: Mayankhttp://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/comment-page-2/#comment-9991 Mayank Thu, 24 Nov 2011 21:22:10 +0000 http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/#comment-9991 Thanks Thanks

]]> By: linglomhttp://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/comment-page-2/#comment-9943 linglom Thu, 10 Nov 2011 14:59:50 +0000 http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/#comment-9943 Robert, For your case, 66.128.0.0/11. Subnet mask is 255.224.0.0 so we are interested in the second octet. The magic number is 256 – 224 = 32. Now subnet number calculation, find the multiple of the magic number that is closest to, but not greater than the the interesting octet of original IP address. It is 32 x 4 = 128 so the subnet number is 66.128.0.0. Next on broadcast address, adding the magic number to the interesting octet of subnet number and subtract 1. It is 32 + 128 – 1 = 159 so the broadcast address is 66.159.255.255. The valid IP address range is 66.128.0.1 - 66.159.255.254 (by adding 1 on the subnet number for first IP and subtract 1 on the broadcast number for last IP). Robert,

For your case, 66.128.0.0/11. Subnet mask is 255.224.0.0 so we are interested in the second octet.

The magic number is 256 – 224 = 32.

Now subnet number calculation, find the multiple of the magic number that is closest to, but not greater than the the interesting octet of original IP address. It is 32 x 4 = 128 so the subnet number is 66.128.0.0.

Next on broadcast address, adding the magic number to the interesting octet of subnet number and subtract 1. It is 32 + 128 – 1 = 159 so the broadcast address is 66.159.255.255.

The valid IP address range is 66.128.0.1 – 66.159.255.254 (by adding 1 on the subnet number for first IP and subtract 1 on the broadcast number for last IP).

]]> By: linglomhttp://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/comment-page-2/#comment-9942 linglom Thu, 10 Nov 2011 14:57:18 +0000 http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/#comment-9942 Sandy, For your case, 192.24.35.128/27. Subnet mask is 255.255.255.224 so we are interested in the fourth octet. The magic number is 256 - 224 = 32. Now subnet number calculation, find the multiple of the magic number that is closest to, but not greater than the the interesting octet of original IP address. It is 32 x 4 = 128 so the subnet number is 198.24.35.128. Next on broadcast address, adding the magic number to the interesting octet of subnet number and subtract 1. It is 32 + 128 – 1 = 159 so the broadcast address is 198.24.35.159. The valid IP address range is 198.24.35.129 – 198.24.35.158 (by adding 1 on the subnet number for first IP and subtract 1 on the broadcast number for last IP). Sandy,

For your case, 192.24.35.128/27. Subnet mask is 255.255.255.224 so we are interested in the fourth octet.

The magic number is 256 – 224 = 32.

Now subnet number calculation, find the multiple of the magic number that is closest to, but not greater than the the interesting octet of original IP address. It is 32 x 4 = 128 so the subnet number is 198.24.35.128.

Next on broadcast address, adding the magic number to the interesting octet of subnet number and subtract 1. It is 32 + 128 – 1 = 159 so the broadcast address is 198.24.35.159.

The valid IP address range is 198.24.35.129 – 198.24.35.158 (by adding 1 on the subnet number for first IP and subtract 1 on the broadcast number for last IP).

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