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	<title>Comments on: How to find IP addresses and subnet number in a few seconds</title>
	<atom:link href="http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/feed/" rel="self" type="application/rss+xml" />
	<link>http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/</link>
	<description>Just another IT weblog</description>
	<lastBuildDate>Fri, 30 Jul 2010 22:18:43 +0000</lastBuildDate>
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	<item>
		<title>By: Qome</title>
		<link>http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/comment-page-1/#comment-6590</link>
		<dc:creator>Qome</dc:creator>
		<pubDate>Tue, 29 Jun 2010 07:42:33 +0000</pubDate>
		<guid isPermaLink="false">http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/#comment-6590</guid>
		<description>How did you obtain the mask 255.255.252 for the ip address 130.4.102.1?</description>
		<content:encoded><![CDATA[<p>How did you obtain the mask 255.255.252 for the ip address 130.4.102.1?</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Kristina</title>
		<link>http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/comment-page-1/#comment-6549</link>
		<dc:creator>Kristina</dc:creator>
		<pubDate>Sat, 12 Jun 2010 00:19:30 +0000</pubDate>
		<guid isPermaLink="false">http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/#comment-6549</guid>
		<description>hey guys , 
this is my question .
host ip 172.30.1.33       Subnet mask 255.255.255.192(/26)

1. consider octet where subnet masks occur _____
2. subnet address for given ip address ______
3. broadcast address for this subnet ______

can u pls help me with these questions .:)

pls explain every step how u did it as i am new to this 
cheers</description>
		<content:encoded><![CDATA[<p>hey guys ,<br />
this is my question .<br />
host ip 172.30.1.33       Subnet mask 255.255.255.192(/26)</p>
<p>1. consider octet where subnet masks occur _____<br />
2. subnet address for given ip address ______<br />
3. broadcast address for this subnet ______</p>
<p>can u pls help me with these questions .:)</p>
<p>pls explain every step how u did it as i am new to this<br />
cheers</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Bhupesh</title>
		<link>http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/comment-page-1/#comment-6457</link>
		<dc:creator>Bhupesh</dc:creator>
		<pubDate>Sun, 16 May 2010 09:35:52 +0000</pubDate>
		<guid isPermaLink="false">http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/#comment-6457</guid>
		<description>Hey Amit:

After researching on these topics for a long time now, I can now calculate these things in a snap... In your case the subnet with ip address 12.200.50.0/17 would be 255.255.128.0 since 12.200.50.0/17 means you have 8+8+1 of subnet ID and this being a class A ip address you have the rest of the part as host bits. Please revert if you need any further information.</description>
		<content:encoded><![CDATA[<p>Hey Amit:</p>
<p>After researching on these topics for a long time now, I can now calculate these things in a snap&#8230; In your case the subnet with ip address 12.200.50.0/17 would be 255.255.128.0 since 12.200.50.0/17 means you have 8+8+1 of subnet ID and this being a class A ip address you have the rest of the part as host bits. Please revert if you need any further information.</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Amit</title>
		<link>http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/comment-page-1/#comment-6453</link>
		<dc:creator>Amit</dc:creator>
		<pubDate>Sat, 15 May 2010 08:46:51 +0000</pubDate>
		<guid isPermaLink="false">http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/#comment-6453</guid>
		<description>Dear, I have a IP 12.200.50.0/17 where the magic number 128 is grather then 50 . so what is the solution for finding subnet number &gt; please reply me 

fasolution@gmail.com</description>
		<content:encoded><![CDATA[<p>Dear, I have a IP 12.200.50.0/17 where the magic number 128 is grather then 50 . so what is the solution for finding subnet number &gt; please reply me </p>
<p><a href="mailto:fasolution@gmail.com">fasolution@gmail.com</a></p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Robin</title>
		<link>http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/comment-page-1/#comment-6427</link>
		<dc:creator>Robin</dc:creator>
		<pubDate>Sun, 09 May 2010 04:26:59 +0000</pubDate>
		<guid isPermaLink="false">http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/#comment-6427</guid>
		<description>Hi Frndz,

Any one pls help me to find the wild card mask range for the IP&#039;s 172.21.188.120 to 172.21.188.140.......</description>
		<content:encoded><![CDATA[<p>Hi Frndz,</p>
<p>Any one pls help me to find the wild card mask range for the IP&#8217;s 172.21.188.120 to 172.21.188.140&#8230;&#8230;.</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: scott</title>
		<link>http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/comment-page-1/#comment-6239</link>
		<dc:creator>scott</dc:creator>
		<pubDate>Tue, 30 Mar 2010 15:38:02 +0000</pubDate>
		<guid isPermaLink="false">http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/#comment-6239</guid>
		<description>Ravi,
hang in there friend. I am working right now.
force yourself to go line by line, step by step with what Linglom has shown us in the mean time. I will get time for this later. He has given us some good stuff.
Scott</description>
		<content:encoded><![CDATA[<p>Ravi,<br />
hang in there friend. I am working right now.<br />
force yourself to go line by line, step by step with what Linglom has shown us in the mean time. I will get time for this later. He has given us some good stuff.<br />
Scott</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Ravi</title>
		<link>http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/comment-page-1/#comment-6238</link>
		<dc:creator>Ravi</dc:creator>
		<pubDate>Tue, 30 Mar 2010 14:58:34 +0000</pubDate>
		<guid isPermaLink="false">http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/#comment-6238</guid>
		<description>Hey Scott:

Help Please...

Regards,

Ravi</description>
		<content:encoded><![CDATA[<p>Hey Scott:</p>
<p>Help Please&#8230;</p>
<p>Regards,</p>
<p>Ravi</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Ravi</title>
		<link>http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/comment-page-1/#comment-6236</link>
		<dc:creator>Ravi</dc:creator>
		<pubDate>Mon, 29 Mar 2010 17:21:08 +0000</pubDate>
		<guid isPermaLink="false">http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/#comment-6236</guid>
		<description>Hi Scott:

Thanks again for your response, however here are my few questions again:

1. As per your calculations is it 1024 valid IP&#039;s available?

2. Can you show me a detailed calculation of my last question that is how to find the subnet and broadcast IP addresses?

I know I am asking too much here but I am really getting into it... and trying to figure out with some easy calculations/maths to figure out the answers to my questions... Hope you would understand... All I need is a step by step calculation of my aforesaid questions as I am new to networking and IP addressing, it will be a pleasure to know the in-depth way of calculating the IP addresses etc... I know Linglom has shown it with an easy math but since I am new to all this I am not able to get it...

Your response would be highly appreciated.

Regards,

Ravi</description>
		<content:encoded><![CDATA[<p>Hi Scott:</p>
<p>Thanks again for your response, however here are my few questions again:</p>
<p>1. As per your calculations is it 1024 valid IP&#8217;s available?</p>
<p>2. Can you show me a detailed calculation of my last question that is how to find the subnet and broadcast IP addresses?</p>
<p>I know I am asking too much here but I am really getting into it&#8230; and trying to figure out with some easy calculations/maths to figure out the answers to my questions&#8230; Hope you would understand&#8230; All I need is a step by step calculation of my aforesaid questions as I am new to networking and IP addressing, it will be a pleasure to know the in-depth way of calculating the IP addresses etc&#8230; I know Linglom has shown it with an easy math but since I am new to all this I am not able to get it&#8230;</p>
<p>Your response would be highly appreciated.</p>
<p>Regards,</p>
<p>Ravi</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: scott</title>
		<link>http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/comment-page-1/#comment-6234</link>
		<dc:creator>scott</dc:creator>
		<pubDate>Mon, 29 Mar 2010 11:57:38 +0000</pubDate>
		<guid isPermaLink="false">http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/#comment-6234</guid>
		<description>Ravi,

to get the 10 bit host, use the powers of 2 like this:
1x2=2
2x2=4
2x4=8
2x8=16
2x16=32
2x32=64
2x64=128
2x128=256
2x256=512
2x512=1024 and so on.... (I referred to this as position 10 for my own convenience)
Now you have your 10 bit position for the hosts.
How else may I help?
Scott

(Linglom, please check these things. Don&#039;t let me show Ravi wrong. I am just answering his questions because I need the challenge.)</description>
		<content:encoded><![CDATA[<p>Ravi,</p>
<p>to get the 10 bit host, use the powers of 2 like this:<br />
1&#215;2=2<br />
2&#215;2=4<br />
2&#215;4=8<br />
2&#215;8=16<br />
2&#215;16=32<br />
2&#215;32=64<br />
2&#215;64=128<br />
2&#215;128=256<br />
2&#215;256=512<br />
2&#215;512=1024 and so on&#8230;. (I referred to this as position 10 for my own convenience)<br />
Now you have your 10 bit position for the hosts.<br />
How else may I help?<br />
Scott</p>
<p>(Linglom, please check these things. Don&#8217;t let me show Ravi wrong. I am just answering his questions because I need the challenge.)</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Ravi</title>
		<link>http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/comment-page-1/#comment-6233</link>
		<dc:creator>Ravi</dc:creator>
		<pubDate>Mon, 29 Mar 2010 06:42:36 +0000</pubDate>
		<guid isPermaLink="false">http://www.linglom.com/2007/02/20/how-to-find-subnet-number-ip-addresses-in-the-subnet-in-a-few-seconds/#comment-6233</guid>
		<description>Hi Scott:

Thank you for your reply, your response is highly appreciated. However if you could show me a detailed calculation it would be greatly appreciated as I am new to this so I am not able to understand what you have shown in the answers above. For example, why we having a 10 bit host etc... if that could be shown here in this space then it would make my life much easy...

I look forward to your explanation...

Thank you so very much for your response.

Regards,

Ravi</description>
		<content:encoded><![CDATA[<p>Hi Scott:</p>
<p>Thank you for your reply, your response is highly appreciated. However if you could show me a detailed calculation it would be greatly appreciated as I am new to this so I am not able to understand what you have shown in the answers above. For example, why we having a 10 bit host etc&#8230; if that could be shown here in this space then it would make my life much easy&#8230;</p>
<p>I look forward to your explanation&#8230;</p>
<p>Thank you so very much for your response.</p>
<p>Regards,</p>
<p>Ravi</p>
]]></content:encoded>
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