Comments on: BizTalk Training 3 – customize filename dynamically

By: Poojith

Poojith — Sun, 25 Jul 2010 10:05:25 +0000

Hi,

I guess this method works only when we use FILE adapter as the receive port. My question is how to name the file dynamically for WCF adapter receive ports?

Hope you can help me with this.

Thank you in advance.

By: linglom

linglom — Thu, 21 Jan 2010 04:26:22 +0000

Hi, Foon Lam
Thanks for correcting, it was my fault.
I have fixed it already.

By: Foon Lam

Foon Lam — Tue, 19 Jan 2010 21:57:45 +0000

I’ve tried out the example and the reason why the output filename is person1.xml and not output_person1.xml is because in the message assignment, “msgPerson2(FILE.ReceivedFileName);” will return you the full path and filename “C:\FILE2\OUT\person1.txt” and not just “person1.txt”, so when you append “output_” to the filename, you get “output_C:\FILE2\OUT\person1.xml”. The send port only uses what’s after the last “\”, so it still ends up as “person1.xml”. To correct this you should use

filename = System.IO.Path.GetFileName(filename.Replace(“.txt”,”.xml”));
filename = “output_” + filename;

instead of just

filename = filename.Replace(“.txt”,”.xml”);
filename = “output_” + filename;

This resolution came courtesy of Thiago Almeida,MVP. If you are interested in reading some of his articles, you can get to his site at “http://connectedthoughts.wordpress.com/”

By: Nigel Bachmann

Nigel Bachmann — Thu, 07 Jan 2010 17:07:15 +0000

Excellent article, exactly what I wanted.

By: Priyan

Priyan — Sun, 04 Oct 2009 15:09:57 +0000

Nice Article. Thanks a lot linglom!

By: Tahir

Tahir — Tue, 16 Dec 2008 17:55:47 +0000

Very nice! It helped me and also solved my problem too.
Thanks

By: linglom

linglom — Fri, 26 Sep 2008 02:00:05 +0000

It was my mistake. The output should be output_person1.xml not person1.xml. I’ll correct it soon.

By: John

John — Wed, 24 Sep 2008 19:13:49 +0000

So where’s the output_person1.txt file? I just see the person1.txt and person1.xml files.